ASVAB Math Knowledge Practice Test 745525

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -a - 5a = -4a - 4z - 6 for a in terms of z.

\(\frac{5}{7}\)z - \(\frac{2}{7}\)
\(\frac{2}{5}\)z + \(\frac{1}{2}\)
\(\frac{1}{3}\)z - 2
-z - 1