| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
acute, obtuse |
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supplementary, vertical |
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vertical, supplementary |
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obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Which of the following expressions contains exactly two terms?
quadratic |
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binomial |
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polynomial |
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monomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Solve for b:
b2 - 12b + 14 = -5b + 4
| -7 or -9 | |
| -6 or -7 | |
| 2 or 5 | |
| 6 or 3 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 12b + 14 = -5b + 4
b2 - 12b + 14 - 4 = -5b
b2 - 12b + 5b + 10 = 0
b2 - 7b + 10 = 0
Next, factor the quadratic equation:
b2 - 7b + 10 = 0
(b - 2)(b - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 2) or (b - 5) must equal zero:
If (b - 2) = 0, b must equal 2
If (b - 5) = 0, b must equal 5
So the solution is that b = 2 or 5
Simplify (y + 3)(y + 3)
| y2 - 9 | |
| 32 | |
| y2 + 6y + 9 | |
| y2 - 6y + 9 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 3)(y + 3)
(y x y) + (y x 3) + (3 x y) + (3 x 3)
y2 + 3y + 3y + 9
y2 + 6y + 9
If side a = 7, side b = 9, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{145} \) | |
| \( \sqrt{130} \) | |
| \( \sqrt{34} \) | |
| \( \sqrt{106} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 72 + 92
c2 = 49 + 81
c2 = 130
c = \( \sqrt{130} \)