When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + c = -7c + 5z - 2 for c in terms of z.
| \(\frac{5}{14}\)z - \(\frac{1}{14}\) | |
| \(\frac{1}{2}\)z - \(\frac{1}{4}\) | |
| -3\(\frac{1}{3}\)z + 2\(\frac{1}{3}\) | |
| z + 1 |