ASVAB Math Knowledge Practice Test 750063 Results

Your Results Global Average
Questions 5 5
Correct 0 3.54
Score 0% 71%

Review

1

The endpoints of this line segment are at (-2, 0) and (2, -6). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x - 3
y = 2x + 1
y = 3x + 3
y = -1\(\frac{1}{2}\)x - 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (0.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)
m = -1\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = -1\(\frac{1}{2}\)x - 3


2

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π d

a = π r2

a = π r

a = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

If the area of this square is 16, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
6\( \sqrt{2} \)
\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)


4

What is 2a - 3a?

80% Answer Correctly
6a2
-1a
a2
6a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a - 3a = -1a


5

If a = 6, b = 9, c = 6, and d = 5, what is the perimeter of this quadrilateral?

88% Answer Correctly
25
26
20
24

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 6 + 9 + 6 + 5
p = 26