ASVAB Math Knowledge Practice Test 750228 Results

Your Results Global Average
Questions 5 5
Correct 0 3.38
Score 0% 68%

Review

1

Simplify 8a x 2b.

85% Answer Correctly
16a2b2
16ab
16\( \frac{b}{a} \)
10ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 2b = (8 x 2) (a x b) = 16ab


2

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

If a = 1, b = 6, c = 2, and d = 4, what is the perimeter of this quadrilateral?

88% Answer Correctly
23
26
13
28

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 1 + 6 + 2 + 4
p = 13


4

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

a2 - c2

c - a

c2 + a2

c2 - a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


5

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
5\( \sqrt{2} \)
8\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)