| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
Simplify 8a x 2b.
| 16a2b2 | |
| 16ab | |
| 16\( \frac{b}{a} \) | |
| 10ab |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
8a x 2b = (8 x 2) (a x b) = 16ab
Which of the following statements about a parallelogram is not true?
a parallelogram is a quadrilateral |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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opposite sides and adjacent angles are equal |
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the area of a parallelogram is base x height |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
If a = 1, b = 6, c = 2, and d = 4, what is the perimeter of this quadrilateral?
| 23 | |
| 26 | |
| 13 | |
| 28 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 1 + 6 + 2 + 4
p = 13
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
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c - a |
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c2 + a2 |
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c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If the area of this square is 1, what is the length of one of the diagonals?
| \( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)