When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + 6c = 2c + 8z - 6 for c in terms of z.
| z - 1\(\frac{1}{2}\) | |
| -\(\frac{1}{8}\)z - \(\frac{1}{8}\) | |
| -\(\frac{2}{11}\)z + \(\frac{6}{11}\) | |
| \(\frac{1}{2}\)z - 1\(\frac{1}{3}\) |