ASVAB Math Knowledge Practice Test 75048 Results

Your Results Global Average
Questions 5 5
Correct 0 3.35
Score 0% 67%

Review

1

This diagram represents two parallel lines with a transversal. If b° = 157, what is the value of y°?

73% Answer Correctly
23
143
157
149

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 157, the value of y° is 157.


2

Simplify 6a x 4b.

86% Answer Correctly
24ab
24\( \frac{a}{b} \)
10ab
24\( \frac{b}{a} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 4b = (6 x 4) (a x b) = 24ab


3

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

92% Answer Correctly

pairs

exponents

division

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


4

Solve -7b + 5b = -9b + 7y + 7 for b in terms of y.

35% Answer Correctly
-y - \(\frac{6}{7}\)
-1\(\frac{4}{7}\)y + \(\frac{6}{7}\)
1\(\frac{2}{9}\)y - \(\frac{5}{9}\)
y + 3\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-7b + 5y = -9b + 7y + 7
-7b = -9b + 7y + 7 - 5y
-7b + 9b = 7y + 7 - 5y
2b = 2y + 7
b = \( \frac{2y + 7}{2} \)
b = \( \frac{2y}{2} \) + \( \frac{7}{2} \)
b = y + 3\(\frac{1}{2}\)


5

The endpoints of this line segment are at (-2, 3) and (2, 5). What is the slope of this line?

46% Answer Correctly
\(\frac{1}{2}\)
2
-3
-\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, 5) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(5.0) - (3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)