| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
Factor y2 + 13y + 40
| (y + 5)(y + 8) | |
| (y - 5)(y + 8) | |
| (y - 5)(y - 8) | |
| (y + 5)(y - 8) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 40 as well and sum (Inside, Outside) to equal 13. For this problem, those two numbers are 5 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 13y + 40
y2 + (5 + 8)y + (5 x 8)
(y + 5)(y + 8)
Which types of triangles will always have at least two sides of equal length?
equilateral and isosceles |
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equilateral, isosceles and right |
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equilateral and right |
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isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
A trapezoid is a quadrilateral with one set of __________ sides.
equal angle |
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equal length |
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right angle |
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parallel |
A trapezoid is a quadrilateral with one set of parallel sides.
If angle a = 26° and angle b = 37° what is the length of angle c?
| 74° | |
| 81° | |
| 117° | |
| 63° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 26° - 37° = 117°
Find the value of c:
3c + z = -8
9c - 2z = 8
| -\(\frac{8}{15}\) | |
| \(\frac{2}{3}\) | |
| -\(\frac{23}{33}\) | |
| \(\frac{14}{15}\) |
You need to find the value of c so solve the first equation in terms of z:
3c + z = -8
z = -8 - 3c
then substitute the result (-8 - 3c) into the second equation:
9c - 2(-8 - 3c) = 8
9c + (-2 x -8) + (-2 x -3c) = 8
9c + 16 + 6c = 8
9c + 6c = 8 - 16
15c = -8
c = \( \frac{-8}{15} \)
c = -\(\frac{8}{15}\)