ASVAB Math Knowledge Practice Test 753042 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

If side a = 7, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{45} \)
\( \sqrt{65} \)
10
\( \sqrt{26} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 72 + 42
c2 = 49 + 16
c2 = 65
c = \( \sqrt{65} \)


2

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π r2

a = π r

a = π d

a = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

Solve for b:
8b - 5 = \( \frac{b}{3} \)

46% Answer Correctly
-1\(\frac{1}{23}\)
2\(\frac{2}{3}\)
\(\frac{15}{23}\)
\(\frac{21}{25}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

8b - 5 = \( \frac{b}{3} \)
3 x (8b - 5) = b
(3 x 8b) + (3 x -5) = b
24b - 15 = b
24b - 15 - b = 0
24b - b = 15
23b = 15
b = \( \frac{15}{23} \)
b = \(\frac{15}{23}\)


4

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

2(π r2) + 2π rh

π r2h2

π r2h

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

2

4

3

5


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.