When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 5c = 5c + 4z + 3 for c in terms of z.
| -2\(\frac{1}{2}\)z + 3\(\frac{1}{2}\) | |
| \(\frac{1}{6}\)z + \(\frac{5}{18}\) | |
| -3z - 1 | |
| \(\frac{11}{13}\)z - \(\frac{9}{13}\) |