| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.50 |
| Score | 0% | 70% |
This diagram represents two parallel lines with a transversal. If b° = 165, what is the value of y°?
| 165 | |
| 169 | |
| 17 | |
| 39 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with b° = 165, the value of y° is 165.
What is the circumference of a circle with a diameter of 15?
| 1π | |
| 15π | |
| 14π | |
| 26π |
The formula for circumference is circle diameter x π:
c = πd
c = 15π
If the area of this square is 9, what is the length of one of the diagonals?
| 9\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
Which of the following statements about math operations is incorrect?
all of these statements are correct |
|
you can subtract monomials that have the same variable and the same exponent |
|
you can multiply monomials that have different variables and different exponents |
|
you can add monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
What is the area of a circle with a diameter of 6?
| 25π | |
| 36π | |
| 49π | |
| 9π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π