When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 5c = 4c - 9z + 1 for c in terms of z.
| \(\frac{7}{9}\)z - \(\frac{5}{9}\) | |
| z - \(\frac{2}{5}\) | |
| -4z + 1 | |
| -6\(\frac{1}{3}\)z - 2\(\frac{2}{3}\) |