When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 4c = 9c + 8y - 7 for c in terms of y.
| \(\frac{1}{3}\)y - \(\frac{1}{3}\) | |
| -\(\frac{2}{3}\)y + \(\frac{3}{4}\) | |
| -y + 1\(\frac{3}{4}\) | |
| 2y + 6 |