ASVAB Math Knowledge Practice Test 756954 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

If angle a = 54° and angle b = 46° what is the length of angle d?

56% Answer Correctly
154°
113°
126°
132°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 54° - 46° = 80°

So, d° = 46° + 80° = 126°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 54° = 126°


2

If a = 5, b = 9, c = 3, and d = 1, what is the perimeter of this quadrilateral?

88% Answer Correctly
16
7
18
11

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 5 + 9 + 3 + 1
p = 18


3

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

all interior angles are right angles

the perimeter is the sum of the lengths of all four sides

the lengths of all sides are equal


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


4

What is the area of a circle with a diameter of 8?

69% Answer Correctly
4π
5π
16π
9π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr2
a = π(42)
a = 16π


5

Solve for y:
-7y - 1 > \( \frac{y}{7} \)

44% Answer Correctly
y > -\(\frac{7}{50}\)
y > \(\frac{21}{25}\)
y > \(\frac{8}{31}\)
y > \(\frac{7}{41}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-7y - 1 > \( \frac{y}{7} \)
7 x (-7y - 1) > y
(7 x -7y) + (7 x -1) > y
-49y - 7 > y
-49y - 7 - y > 0
-49y - y > 7
-50y > 7
y > \( \frac{7}{-50} \)
y > -\(\frac{7}{50}\)