| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
This diagram represents two parallel lines with a transversal. If x° = 149, what is the value of w°?
| 31 | |
| 156 | |
| 22 | |
| 17 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with x° = 149, the value of w° is 31.
If a = c = 7, b = d = 2, and the blue angle = 80°, what is the area of this parallelogram?
| 9 | |
| 16 | |
| 14 | |
| 12 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 7 x 2
a = 14
The endpoints of this line segment are at (-2, 1) and (2, -7). What is the slope-intercept equation for this line?
| y = 2x - 1 | |
| y = -2x - 3 | |
| y = -2x + 1 | |
| y = -2x - 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -7) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-7.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)Plugging these values into the slope-intercept equation:
y = -2x - 3
What is 4a9 + 3a9?
| 7a18 | |
| 7a9 | |
| 7 | |
| 12a9 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a9 + 3a9 = 7a9
Solve for c:
-9c + 8 = \( \frac{c}{3} \)
| \(\frac{6}{7}\) | |
| 1\(\frac{13}{23}\) | |
| 1\(\frac{1}{55}\) | |
| -1 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9c + 8 = \( \frac{c}{3} \)
3 x (-9c + 8) = c
(3 x -9c) + (3 x 8) = c
-27c + 24 = c
-27c + 24 - c = 0
-27c - c = -24
-28c = -24
c = \( \frac{-24}{-28} \)
c = \(\frac{6}{7}\)