| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
A trapezoid is a quadrilateral with one set of __________ sides.
right angle |
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parallel |
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equal angle |
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equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
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equilateral and right |
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equilateral and isosceles |
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equilateral, isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Solve for b:
b2 - 14b + 34 = -2b - 1
| 5 or 7 | |
| -1 or -5 | |
| 3 or 1 | |
| 4 or -4 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 14b + 34 = -2b - 1
b2 - 14b + 34 + 1 = -2b
b2 - 14b + 2b + 35 = 0
b2 - 12b + 35 = 0
Next, factor the quadratic equation:
b2 - 12b + 35 = 0
(b - 5)(b - 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 5) or (b - 7) must equal zero:
If (b - 5) = 0, b must equal 5
If (b - 7) = 0, b must equal 7
So the solution is that b = 5 or 7
Which of the following statements about a triangle is not true?
perimeter = sum of side lengths |
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area = ½bh |
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exterior angle = sum of two adjacent interior angles |
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sum of interior angles = 180° |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for a:
-a + 1 < \( \frac{a}{6} \)
| a < -1\(\frac{1}{19}\) | |
| a < 1\(\frac{9}{19}\) | |
| a < \(\frac{6}{7}\) | |
| a < \(\frac{8}{17}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-a + 1 < \( \frac{a}{6} \)
6 x (-a + 1) < a
(6 x -a) + (6 x 1) < a
-6a + 6 < a
-6a + 6 - a < 0
-6a - a < -6
-7a < -6
a < \( \frac{-6}{-7} \)
a < \(\frac{6}{7}\)