| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
What is the circumference of a circle with a radius of 9?
| 18π | |
| 3π | |
| 10π | |
| 2π |
The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:
c = πd
c = π(2 * r)
c = π(2 * 9)
c = 18π
If the area of this square is 4, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
The endpoints of this line segment are at (-2, 8) and (2, 0). What is the slope-intercept equation for this line?
| y = 1\(\frac{1}{2}\)x + 1 | |
| y = -2x + 4 | |
| y = -x - 1 | |
| y = \(\frac{1}{2}\)x - 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 8) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (8.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)Plugging these values into the slope-intercept equation:
y = -2x + 4
What is 8a3 + 6a3?
| 2 | |
| 14 | |
| 2a6 | |
| 14a3 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a3 + 6a3 = 14a3
Solve for b:
b2 + 2b - 24 = 0
| 6 or 5 | |
| 4 or -6 | |
| 8 or -8 | |
| 7 or -5 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 + 2b - 24 = 0
(b - 4)(b + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 4) or (b + 6) must equal zero:
If (b - 4) = 0, b must equal 4
If (b + 6) = 0, b must equal -6
So the solution is that b = 4 or -6