ASVAB Math Knowledge Practice Test 760728 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

The dimensions of this trapezoid are a = 4, b = 6, c = 7, d = 3, and h = 2. What is the area?

51% Answer Correctly
18
9
22\(\frac{1}{2}\)
16

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 3)(2)
a = ½(9)(2)
a = ½(18) = \( \frac{18}{2} \)
a = 9


2

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can add monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents

all of these statements are correct

you can subtract monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


3

Solve for b:
7b - 2 = -1 - 3b

59% Answer Correctly
\(\frac{1}{10}\)
1
\(\frac{7}{8}\)
-\(\frac{4}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

7b - 2 = -1 - 3b
7b = -1 - 3b + 2
7b + 3b = -1 + 2
10b = 1
b = \( \frac{1}{10} \)
b = \(\frac{1}{10}\)


4

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

68% Answer Correctly

h2 x l2 x w2

h x l x w

2lw x 2wh + 2lh

lw x wh + lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


5

Find the value of c:
-7c + y = 1
-2c - 6y = -2

42% Answer Correctly
-1\(\frac{13}{37}\)
-1
\(\frac{17}{25}\)
-\(\frac{1}{11}\)

Solution

You need to find the value of c so solve the first equation in terms of y:

-7c + y = 1
y = 1 + 7c

then substitute the result (1 - -7c) into the second equation:

-2c - 6(1 + 7c) = -2
-2c + (-6 x 1) + (-6 x 7c) = -2
-2c - 6 - 42c = -2
-2c - 42c = -2 + 6
-44c = 4
c = \( \frac{4}{-44} \)
c = -\(\frac{1}{11}\)