| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
Order the following types of angle from least number of degrees to most number of degrees.
right, obtuse, acute |
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right, acute, obtuse |
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acute, obtuse, right |
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acute, right, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
On this circle, line segment CD is the:
chord |
|
circumference |
|
radius |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If the area of this square is 1, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)
Find the value of c:
3c + z = -5
8c + 6z = 3
| -3\(\frac{3}{10}\) | |
| 2\(\frac{7}{13}\) | |
| -\(\frac{7}{20}\) | |
| 1 |
You need to find the value of c so solve the first equation in terms of z:
3c + z = -5
z = -5 - 3c
then substitute the result (-5 - 3c) into the second equation:
8c + 6(-5 - 3c) = 3
8c + (6 x -5) + (6 x -3c) = 3
8c - 30 - 18c = 3
8c - 18c = 3 + 30
-10c = 33
c = \( \frac{33}{-10} \)
c = -3\(\frac{3}{10}\)
If a = 1 and x = 4, what is the value of 7a(a - x)?
| 81 | |
| -21 | |
| -384 | |
| 0 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
7a(a - x)
7(1)(1 - 4)
7(1)(-3)
(7)(-3)
-21