| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
Solve for y:
9y - 2 = -3 + 4y
| -\(\frac{1}{5}\) | |
| 2\(\frac{1}{4}\) | |
| -5 | |
| -1\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
9y - 2 = -3 + 4y
9y = -3 + 4y + 2
9y - 4y = -3 + 2
5y = -1
y = \( \frac{-1}{5} \)
y = -\(\frac{1}{5}\)
Find the value of b:
-8b + x = 1
-7b - 4x = -1
| -\(\frac{43}{51}\) | |
| -\(\frac{1}{13}\) | |
| -3\(\frac{1}{2}\) | |
| \(\frac{1}{7}\) |
You need to find the value of b so solve the first equation in terms of x:
-8b + x = 1
x = 1 + 8b
then substitute the result (1 - -8b) into the second equation:
-7b - 4(1 + 8b) = -1
-7b + (-4 x 1) + (-4 x 8b) = -1
-7b - 4 - 32b = -1
-7b - 32b = -1 + 4
-39b = 3
b = \( \frac{3}{-39} \)
b = -\(\frac{1}{13}\)
Solve for b:
b2 - 5b + 6 = 0
| 2 or 3 | |
| -8 or -8 | |
| 8 or 3 | |
| 4 or 1 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 - 5b + 6 = 0
(b - 2)(b - 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 2) or (b - 3) must equal zero:
If (b - 2) = 0, b must equal 2
If (b - 3) = 0, b must equal 3
So the solution is that b = 2 or 3
If side x = 12cm, side y = 9cm, and side z = 12cm what is the perimeter of this triangle?
| 22cm | |
| 34cm | |
| 36cm | |
| 33cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 12cm + 9cm + 12cm = 33cm
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
|
factoring |
|
deconstructing |
|
normalizing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.