When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 2c = -9c + 6z + 6 for c in terms of z.
| \(\frac{5}{8}\)z - \(\frac{3}{4}\) | |
| -2\(\frac{1}{3}\)z - 2\(\frac{1}{3}\) | |
| 1\(\frac{1}{3}\)z - \(\frac{1}{9}\) | |
| z + 1\(\frac{1}{2}\) |