ASVAB Math Knowledge Practice Test 76393 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

Solve for b:
2b + 9 < \( \frac{b}{3} \)

44% Answer Correctly
b < -5\(\frac{2}{5}\)
b < 2\(\frac{4}{5}\)
b < -\(\frac{5}{8}\)
b < -\(\frac{10}{41}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

2b + 9 < \( \frac{b}{3} \)
3 x (2b + 9) < b
(3 x 2b) + (3 x 9) < b
6b + 27 < b
6b + 27 - b < 0
6b - b < -27
5b < -27
b < \( \frac{-27}{5} \)
b < -5\(\frac{2}{5}\)


2

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

π r2h

4π r2

2(π r2) + 2π rh

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

If side a = 2, side b = 6, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{98} \)
\( \sqrt{40} \)
\( \sqrt{34} \)
\( \sqrt{45} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 62
c2 = 4 + 36
c2 = 40
c = \( \sqrt{40} \)


4

The dimensions of this cube are height (h) = 8, length (l) = 4, and width (w) = 5. What is the surface area?

51% Answer Correctly
262
62
198
184

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 5) + (2 x 5 x 8) + (2 x 4 x 8)
sa = (40) + (80) + (64)
sa = 184


5

The dimensions of this cube are height (h) = 4, length (l) = 1, and width (w) = 6. What is the volume?

82% Answer Correctly
28
24
108
252

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 4 x 1 x 6
v = 24