| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
Solve for b:
2b + 9 < \( \frac{b}{3} \)
| b < -5\(\frac{2}{5}\) | |
| b < 2\(\frac{4}{5}\) | |
| b < -\(\frac{5}{8}\) | |
| b < -\(\frac{10}{41}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
2b + 9 < \( \frac{b}{3} \)
3 x (2b + 9) < b
(3 x 2b) + (3 x 9) < b
6b + 27 < b
6b + 27 - b < 0
6b - b < -27
5b < -27
b < \( \frac{-27}{5} \)
b < -5\(\frac{2}{5}\)
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
4π r2 |
|
2(π r2) + 2π rh |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
If side a = 2, side b = 6, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{98} \) | |
| \( \sqrt{40} \) | |
| \( \sqrt{34} \) | |
| \( \sqrt{45} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 62
c2 = 4 + 36
c2 = 40
c = \( \sqrt{40} \)
The dimensions of this cube are height (h) = 8, length (l) = 4, and width (w) = 5. What is the surface area?
| 262 | |
| 62 | |
| 198 | |
| 184 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 5) + (2 x 5 x 8) + (2 x 4 x 8)
sa = (40) + (80) + (64)
sa = 184
The dimensions of this cube are height (h) = 4, length (l) = 1, and width (w) = 6. What is the volume?
| 28 | |
| 24 | |
| 108 | |
| 252 |
The volume of a cube is height x length x width:
v = h x l x w
v = 4 x 1 x 6
v = 24