When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b - 5b = -3b + 6z + 9 for b in terms of z.
| 2\(\frac{1}{5}\)z + 1\(\frac{1}{5}\) | |
| z - 3 | |
| 1\(\frac{2}{9}\)z + 1 | |
| -1\(\frac{1}{3}\)z + \(\frac{5}{12}\) |