| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
A right angle measures:
180° |
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360° |
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45° |
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90° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
What is 9a8 + 9a8?
| 16 | |
| 0 | |
| 81a8 | |
| 18a8 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
9a8 + 9a8 = 18a8
If angle a = 68° and angle b = 47° what is the length of angle d?
| 118° | |
| 112° | |
| 131° | |
| 150° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 68° - 47° = 65°
So, d° = 47° + 65° = 112°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 68° = 112°
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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obtuse, acute |
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acute, obtuse |
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vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Solve for y:
y2 + 9y + 29 = -2y - 1
| -5 or -6 | |
| 9 or 7 | |
| -5 or -8 | |
| 1 or -2 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + 9y + 29 = -2y - 1
y2 + 9y + 29 + 1 = -2y
y2 + 9y + 2y + 30 = 0
y2 + 11y + 30 = 0
Next, factor the quadratic equation:
y2 + 11y + 30 = 0
(y + 5)(y + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 5) or (y + 6) must equal zero:
If (y + 5) = 0, y must equal -5
If (y + 6) = 0, y must equal -6
So the solution is that y = -5 or -6