ASVAB Math Knowledge Practice Test 765435 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

the lengths of all sides are equal

the area is length x width

all interior angles are right angles


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

On this circle, line segment CD is the:

46% Answer Correctly

chord

circumference

diameter

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

If a = c = 8, b = d = 5, and the blue angle = 79°, what is the area of this parallelogram?

65% Answer Correctly
7
54
40
16

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 8 x 5
a = 40


4

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
4\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


5

If BD = 16 and AD = 21, AB = ?

76% Answer Correctly
15
13
14
5

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 21 - 16
AB = 5