ASVAB Math Knowledge Practice Test 766050 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

What is 2a - 6a?

79% Answer Correctly
8a2
-4a
12a
8

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a - 6a = -4a


2

The dimensions of this cylinder are height (h) = 2 and radius (r) = 8. What is the surface area?

48% Answer Correctly
60π
72π
160π
224π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 2)
sa = 2π(64) + 2π(16)
sa = (2 x 64)π + (2 x 16)π
sa = 128π + 32π
sa = 160π


3

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

factoring

deconstructing

squaring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


4

On this circle, line segment AB is the:

70% Answer Correctly

chord

circumference

diameter

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
6\( \sqrt{2} \)
7\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)