| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.36 |
| Score | 0% | 47% |
On this circle, line segment CD is the:
radius |
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diameter |
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circumference |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
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trisects |
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midpoints |
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intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If c = -7 and y = 2, what is the value of -4c(c - y)?
| -252 | |
| 0 | |
| 14 | |
| -672 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-4c(c - y)
-4(-7)(-7 - 2)
-4(-7)(-9)
(28)(-9)
-252
Solve -6c + 2c = 4c + 8y - 3 for c in terms of y.
| 1\(\frac{4}{9}\)y - \(\frac{2}{3}\) | |
| y + 2\(\frac{1}{2}\) | |
| -1\(\frac{2}{3}\)y + 1 | |
| -\(\frac{3}{5}\)y + \(\frac{3}{10}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-6c + 2y = 4c + 8y - 3
-6c = 4c + 8y - 3 - 2y
-6c - 4c = 8y - 3 - 2y
-10c = 6y - 3
c = \( \frac{6y - 3}{-10} \)
c = \( \frac{6y}{-10} \) + \( \frac{-3}{-10} \)
c = -\(\frac{3}{5}\)y + \(\frac{3}{10}\)
Find the value of b:
6b + z = -8
-5b - 6z = 3
| -3\(\frac{2}{9}\) | |
| -1\(\frac{14}{31}\) | |
| 3\(\frac{3}{7}\) | |
| -2\(\frac{3}{4}\) |
You need to find the value of b so solve the first equation in terms of z:
6b + z = -8
z = -8 - 6b
then substitute the result (-8 - 6b) into the second equation:
-5b - 6(-8 - 6b) = 3
-5b + (-6 x -8) + (-6 x -6b) = 3
-5b + 48 + 36b = 3
-5b + 36b = 3 - 48
31b = -45
b = \( \frac{-45}{31} \)
b = -1\(\frac{14}{31}\)