When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a + a = 5a - 6z - 1 for a in terms of z.
| z - 9 | |
| 3\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| 1\(\frac{2}{3}\)z + 3 | |
| \(\frac{1}{15}\)z + \(\frac{2}{5}\) |