ASVAB Math Knowledge Practice Test 771145 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

If a = c = 5, b = d = 7, what is the area of this rectangle?

80% Answer Correctly
20
24
21
35

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 5 x 7
a = 35


2

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π r

a = π r2

a = π d2

a = π d


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

Solve -7b + 10b = 4b - 9x - 9 for b in terms of x.

34% Answer Correctly
x + \(\frac{1}{2}\)
1\(\frac{8}{11}\)x + \(\frac{9}{11}\)
3\(\frac{1}{4}\)x - \(\frac{3}{4}\)
\(\frac{5}{9}\)x - \(\frac{5}{9}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-7b + 10x = 4b - 9x - 9
-7b = 4b - 9x - 9 - 10x
-7b - 4b = -9x - 9 - 10x
-11b = -19x - 9
b = \( \frac{-19x - 9}{-11} \)
b = \( \frac{-19x}{-11} \) + \( \frac{-9}{-11} \)
b = 1\(\frac{8}{11}\)x + \(\frac{9}{11}\)


4

Solve for c:
c2 - 5c + 4 = 0

58% Answer Correctly
-3 or -7
1 or 4
5 or -6
2 or -6

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 - 5c + 4 = 0
(c - 1)(c - 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 1) or (c - 4) must equal zero:

If (c - 1) = 0, c must equal 1
If (c - 4) = 0, c must equal 4

So the solution is that c = 1 or 4


5

The dimensions of this cube are height (h) = 2, length (l) = 2, and width (w) = 4. What is the surface area?

51% Answer Correctly
72
40
172
144

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 2 x 4) + (2 x 4 x 2) + (2 x 2 x 2)
sa = (16) + (16) + (8)
sa = 40