| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
If a = c = 5, b = d = 7, what is the area of this rectangle?
| 20 | |
| 24 | |
| 21 | |
| 35 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 5 x 7
a = 35
The formula for the area of a circle is which of the following?
a = π r |
|
a = π r2 |
|
a = π d2 |
|
a = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve -7b + 10b = 4b - 9x - 9 for b in terms of x.
| x + \(\frac{1}{2}\) | |
| 1\(\frac{8}{11}\)x + \(\frac{9}{11}\) | |
| 3\(\frac{1}{4}\)x - \(\frac{3}{4}\) | |
| \(\frac{5}{9}\)x - \(\frac{5}{9}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-7b + 10x = 4b - 9x - 9
-7b = 4b - 9x - 9 - 10x
-7b - 4b = -9x - 9 - 10x
-11b = -19x - 9
b = \( \frac{-19x - 9}{-11} \)
b = \( \frac{-19x}{-11} \) + \( \frac{-9}{-11} \)
b = 1\(\frac{8}{11}\)x + \(\frac{9}{11}\)
Solve for c:
c2 - 5c + 4 = 0
| -3 or -7 | |
| 1 or 4 | |
| 5 or -6 | |
| 2 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
c2 - 5c + 4 = 0
(c - 1)(c - 4) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 1) or (c - 4) must equal zero:
If (c - 1) = 0, c must equal 1
If (c - 4) = 0, c must equal 4
So the solution is that c = 1 or 4
The dimensions of this cube are height (h) = 2, length (l) = 2, and width (w) = 4. What is the surface area?
| 72 | |
| 40 | |
| 172 | |
| 144 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 2 x 4) + (2 x 4 x 2) + (2 x 2 x 2)
sa = (16) + (16) + (8)
sa = 40