| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.69 |
| Score | 0% | 54% |
What is the area of a circle with a diameter of 10?
| 64π | |
| 25π | |
| 81π | |
| 7π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{10}{2} \)
r = 5
a = πr2
a = π(52)
a = 25π
Solve for b:
b2 - 4b + 3 = 0
| 9 or 6 | |
| 8 or 5 | |
| 1 or 3 | |
| 9 or 3 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 - 4b + 3 = 0
(b - 1)(b - 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 1) or (b - 3) must equal zero:
If (b - 1) = 0, b must equal 1
If (b - 3) = 0, b must equal 3
So the solution is that b = 1 or 3
Simplify (2a)(4ab) + (9a2)(6b).
| -46ab2 | |
| 46ab2 | |
| 90ab2 | |
| 62a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(4ab) + (9a2)(6b)
(2 x 4)(a x a x b) + (9 x 6)(a2 x b)
(8)(a1+1 x b) + (54)(a2b)
8a2b + 54a2b
62a2b
Factor y2 + 6y + 9
| (y + 3)(y - 3) | |
| (y - 3)(y + 3) | |
| (y + 3)(y + 3) | |
| (y - 3)(y - 3) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 9 as well and sum (Inside, Outside) to equal 6. For this problem, those two numbers are 3 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 6y + 9
y2 + (3 + 3)y + (3 x 3)
(y + 3)(y + 3)
The formula for the area of a circle is which of the following?
c = π d |
|
c = π r2 |
|
c = π r |
|
c = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.