ASVAB Math Knowledge Practice Test 773553 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

If the base of this triangle is 1 and the height is 1, what is the area?

58% Answer Correctly
44
\(\frac{1}{2}\)
28
42

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 1 = \( \frac{1}{2} \) = \(\frac{1}{2}\)


2

The dimensions of this cube are height (h) = 9, length (l) = 4, and width (w) = 2. What is the surface area?

51% Answer Correctly
102
94
124
188

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 2) + (2 x 2 x 9) + (2 x 4 x 9)
sa = (16) + (36) + (72)
sa = 124


3

This diagram represents two parallel lines with a transversal. If d° = 142, what is the value of c°?

73% Answer Correctly
14
26
20
38

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with d° = 142, the value of c° is 38.


4

The dimensions of this cylinder are height (h) = 7 and radius (r) = 8. What is the surface area?

48% Answer Correctly
288π
168π
20π
240π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 7)
sa = 2π(64) + 2π(56)
sa = (2 x 64)π + (2 x 56)π
sa = 128π + 112π
sa = 240π


5

What is the circumference of a circle with a diameter of 8?

71% Answer Correctly
11π
19π
16π

Solution

The formula for circumference is circle diameter x π:

c = πd
c = 8π