ASVAB Math Knowledge Practice Test 77617 Results

Your Results Global Average
Questions 5 5
Correct 0 2.66
Score 0% 53%

Review

1

If the base of this triangle is 3 and the height is 1, what is the area?

58% Answer Correctly
55
35
67\(\frac{1}{2}\)
1\(\frac{1}{2}\)

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 3 x 1 = \( \frac{3}{2} \) = 1\(\frac{1}{2}\)


2

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

quadrilateral

triangle

rhombus

trapezoid


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


3

Solve 8a + 9a = -4a - 6z - 2 for a in terms of z.

34% Answer Correctly
\(\frac{5}{8}\)z + \(\frac{5}{8}\)
\(\frac{1}{2}\)z + \(\frac{7}{10}\)
-1\(\frac{3}{5}\)z + \(\frac{1}{5}\)
-1\(\frac{1}{4}\)z - \(\frac{1}{6}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

8a + 9z = -4a - 6z - 2
8a = -4a - 6z - 2 - 9z
8a + 4a = -6z - 2 - 9z
12a = -15z - 2
a = \( \frac{-15z - 2}{12} \)
a = \( \frac{-15z}{12} \) + \( \frac{-2}{12} \)
a = -1\(\frac{1}{4}\)z - \(\frac{1}{6}\)


4

Solve for y:
y2 + 7y + 11 = y + 2

48% Answer Correctly
9 or -1
-3
5 or 1
5 or -7

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 + 7y + 11 = y + 2
y2 + 7y + 11 - 2 = y
y2 + 7y - y + 9 = 0
y2 + 6y + 9 = 0

Next, factor the quadratic equation:

y2 + 6y + 9 = 0
(y + 3)(y + 3) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (y + 3) must equal zero:

If (y + 3) = 0, y must equal -3

So the solution is that y = -3


5

What is 7a2 - 8a2?

73% Answer Correctly
a24
15a4
56a2
-1a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a2 - 8a2 = -1a2