| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
On this circle, line segment AB is the:
circumference |
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chord |
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diameter |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
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right, acute, obtuse |
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right, obtuse, acute |
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acute, obtuse, right |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If the area of this square is 64, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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exterior angle = sum of two adjacent interior angles |
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area = ½bh |
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perimeter = sum of side lengths |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for a:
a - 7 = \( \frac{a}{-9} \)
| -1\(\frac{8}{55}\) | |
| -1\(\frac{1}{3}\) | |
| -\(\frac{27}{35}\) | |
| 6\(\frac{3}{10}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
a - 7 = \( \frac{a}{-9} \)
-9 x (a - 7) = a
(-9 x a) + (-9 x -7) = a
-9a + 63 = a
-9a + 63 - a = 0
-9a - a = -63
-10a = -63
a = \( \frac{-63}{-10} \)
a = 6\(\frac{3}{10}\)