| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
If side x = 5cm, side y = 11cm, and side z = 5cm what is the perimeter of this triangle?
| 21cm | |
| 31cm | |
| 24cm | |
| 33cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 5cm + 11cm + 5cm = 21cm
Simplify (4a)(2ab) - (8a2)(8b).
| 72a2b | |
| 72ab2 | |
| 96a2b | |
| -56a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(2ab) - (8a2)(8b)
(4 x 2)(a x a x b) - (8 x 8)(a2 x b)
(8)(a1+1 x b) - (64)(a2b)
8a2b - 64a2b
-56a2b
If the area of this square is 9, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
acute, obtuse |
|
vertical, supplementary |
|
supplementary, vertical |
|
obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Solve for x:
x2 - x - 56 = 0
| -4 or -5 | |
| -7 or 8 | |
| -3 or -9 | |
| 2 or -4 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 - x - 56 = 0
(x + 7)(x - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 7) or (x - 8) must equal zero:
If (x + 7) = 0, x must equal -7
If (x - 8) = 0, x must equal 8
So the solution is that x = -7 or 8