ASVAB Math Knowledge Practice Test 77886 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

If side x = 5cm, side y = 11cm, and side z = 5cm what is the perimeter of this triangle?

84% Answer Correctly
21cm
31cm
24cm
33cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 5cm + 11cm + 5cm = 21cm


2

Simplify (4a)(2ab) - (8a2)(8b).

62% Answer Correctly
72a2b
72ab2
96a2b
-56a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(2ab) - (8a2)(8b)
(4 x 2)(a x a x b) - (8 x 8)(a2 x b)
(8)(a1+1 x b) - (64)(a2b)
8a2b - 64a2b
-56a2b


3

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
2\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


4

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

acute, obtuse

vertical, supplementary

supplementary, vertical

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


5

Solve for x:
x2 - x - 56 = 0

58% Answer Correctly
-4 or -5
-7 or 8
-3 or -9
2 or -4

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

x2 - x - 56 = 0
(x + 7)(x - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 7) or (x - 8) must equal zero:

If (x + 7) = 0, x must equal -7
If (x - 8) = 0, x must equal 8

So the solution is that x = -7 or 8