To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

6b - 4 > 8 + 5b
6b > 8 + 5b + 4
6b - 5b > 8 + 4
b > 12

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c² + 3c - 40 = 0
(c - 5)(c + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 5) or (c + 8) must equal zero:

If (c - 5) = 0, c must equal 5
If (c + 8) = 0, c must equal -8

So the solution is that c = 5 or -8

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -56 as well and sum (Inside, Outside) to equal 1. For this problem, those two numbers are -7 and 8. Then, plug these into a set of binomials using the square root of the First variable (y²):

y² + y - 56
y² + (-7 + 8)y + (-7 x 8)
(y - 7)(y + 8)

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

5b(b - z)
5(1)(1 + 8)
5(1)(9)
(5)(9)
45