| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.58 |
| Score | 0% | 52% |
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
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isosceles and right |
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equilateral, isosceles and right |
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equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Find the value of c:
-c + x = -6
8c - 4x = -2
| \(\frac{4}{11}\) | |
| 4\(\frac{3}{5}\) | |
| -6\(\frac{1}{2}\) | |
| 1 |
You need to find the value of c so solve the first equation in terms of x:
-c + x = -6
x = -6 + c
then substitute the result (-6 - -1c) into the second equation:
8c - 4(-6 + c) = -2
8c + (-4 x -6) + (-4 x c) = -2
8c + 24 - 4c = -2
8c - 4c = -2 - 24
4c = -26
c = \( \frac{-26}{4} \)
c = -6\(\frac{1}{2}\)
On this circle, a line segment connecting point A to point D is called:
radius |
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chord |
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circumference |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this cube are height (h) = 9, length (l) = 6, and width (w) = 8. What is the volume?
| 432 | |
| 336 | |
| 30 | |
| 96 |
The volume of a cube is height x length x width:
v = h x l x w
v = 9 x 6 x 8
v = 432
Solve -7b - 5b = 5b - 6y + 4 for b in terms of y.
| \(\frac{3}{4}\)y + \(\frac{3}{4}\) | |
| 2y - 4 | |
| \(\frac{1}{2}\)y + \(\frac{1}{2}\) | |
| \(\frac{1}{12}\)y - \(\frac{1}{3}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-7b - 5y = 5b - 6y + 4
-7b = 5b - 6y + 4 + 5y
-7b - 5b = -6y + 4 + 5y
-12b = -y + 4
b = \( \frac{-y + 4}{-12} \)
b = \( \frac{-y}{-12} \) + \( \frac{4}{-12} \)
b = \(\frac{1}{12}\)y - \(\frac{1}{3}\)