ASVAB Math Knowledge Practice Test 780668 Results

Your Results Global Average
Questions 5 5
Correct 0 2.58
Score 0% 52%

Review

1

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

isosceles and right

equilateral, isosceles and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


2

Find the value of c:
-c + x = -6
8c - 4x = -2

42% Answer Correctly
\(\frac{4}{11}\)
4\(\frac{3}{5}\)
-6\(\frac{1}{2}\)
1

Solution

You need to find the value of c so solve the first equation in terms of x:

-c + x = -6
x = -6 + c

then substitute the result (-6 - -1c) into the second equation:

8c - 4(-6 + c) = -2
8c + (-4 x -6) + (-4 x c) = -2
8c + 24 - 4c = -2
8c - 4c = -2 - 24
4c = -26
c = \( \frac{-26}{4} \)
c = -6\(\frac{1}{2}\)


3

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

radius

chord

circumference

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

The dimensions of this cube are height (h) = 9, length (l) = 6, and width (w) = 8. What is the volume?

83% Answer Correctly
432
336
30
96

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 9 x 6 x 8
v = 432


5

Solve -7b - 5b = 5b - 6y + 4 for b in terms of y.

34% Answer Correctly
\(\frac{3}{4}\)y + \(\frac{3}{4}\)
2y - 4
\(\frac{1}{2}\)y + \(\frac{1}{2}\)
\(\frac{1}{12}\)y - \(\frac{1}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-7b - 5y = 5b - 6y + 4
-7b = 5b - 6y + 4 + 5y
-7b - 5b = -6y + 4 + 5y
-12b = -y + 4
b = \( \frac{-y + 4}{-12} \)
b = \( \frac{-y}{-12} \) + \( \frac{4}{-12} \)
b = \(\frac{1}{12}\)y - \(\frac{1}{3}\)