ASVAB Math Knowledge Practice Test 781998 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

Simplify (y + 1)(y - 8)

62% Answer Correctly
y2 + 7y - 8
y2 + 9y + 8
y2 - 7y - 8
y2 - 9y + 8

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 1)(y - 8)
(y x y) + (y x -8) + (1 x y) + (1 x -8)
y2 - 8y + y - 8
y2 - 7y - 8


2

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
2\( \sqrt{2} \)
9\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


3

What is the area of a circle with a diameter of 4?

69% Answer Correctly
4π
7π
5π
8π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{4}{2} \)
r = 2
a = πr2
a = π(22)
a = 4π


4

Solve 8a + 4a = -9a + x - 7 for a in terms of x.

34% Answer Correctly
-x - \(\frac{6}{7}\)
\(\frac{4}{5}\)x - \(\frac{3}{5}\)
-\(\frac{3}{17}\)x - \(\frac{7}{17}\)
x - \(\frac{1}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

8a + 4x = -9a + x - 7
8a = -9a + x - 7 - 4x
8a + 9a = x - 7 - 4x
17a = -3x - 7
a = \( \frac{-3x - 7}{17} \)
a = \( \frac{-3x}{17} \) + \( \frac{-7}{17} \)
a = -\(\frac{3}{17}\)x - \(\frac{7}{17}\)


5

What is 5a2 + 3a2?

74% Answer Correctly
8a2
2
a24
2a4

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a2 + 3a2 = 8a2