When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 2c = -3c - y - 1 for c in terms of y.
| -\(\frac{1}{2}\)y - \(\frac{1}{6}\) | |
| 2y + 4 | |
| -\(\frac{2}{7}\)y + \(\frac{1}{7}\) | |
| 1\(\frac{1}{2}\)y + 1\(\frac{1}{6}\) |