| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.63 |
| Score | 0% | 73% |
What is 2a3 + 9a3?
| 11a3 | |
| -7a6 | |
| 11a6 | |
| a36 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
2a3 + 9a3 = 11a3
Factor y2 + 3y - 10
| (y - 2)(y + 5) | |
| (y + 2)(y + 5) | |
| (y - 2)(y - 5) | |
| (y + 2)(y - 5) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -10 as well and sum (Inside, Outside) to equal 3. For this problem, those two numbers are -2 and 5. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 3y - 10
y2 + (-2 + 5)y + (-2 x 5)
(y - 2)(y + 5)
If side x = 7cm, side y = 11cm, and side z = 7cm what is the perimeter of this triangle?
| 20cm | |
| 31cm | |
| 32cm | |
| 25cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 7cm + 11cm + 7cm = 25cm
If the area of this square is 36, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)
What is 3a - 2a?
| a2 | |
| 6a | |
| 1a | |
| 5 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
3a - 2a = 1a