ASVAB Math Knowledge Practice Test 784853 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

The endpoints of this line segment are at (-2, 6) and (2, -6). What is the slope of this line?

46% Answer Correctly
-1
-3
-\(\frac{1}{2}\)
-1\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)
m = -3


2

If a = 5, b = 2, c = 1, and d = 4, what is the perimeter of this quadrilateral?

88% Answer Correctly
14
23
12
18

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 5 + 2 + 1 + 4
p = 12


3

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

triangle

quadrilateral

trapezoid

rhombus


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


4

What is 2a8 + 8a8?

74% Answer Correctly
-6
10a8
-6a16
10

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a8 + 8a8 = 10a8


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
5\( \sqrt{2} \)
2\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)