| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.73 |
| Score | 0% | 55% |
Simplify (3a)(8ab) + (4a2)(3b).
| -12a2b | |
| 36a2b | |
| 12ab2 | |
| -12ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(8ab) + (4a2)(3b)
(3 x 8)(a x a x b) + (4 x 3)(a2 x b)
(24)(a1+1 x b) + (12)(a2b)
24a2b + 12a2b
36a2b
A(n) __________ is to a parallelogram as a square is to a rectangle.
rhombus |
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trapezoid |
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triangle |
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quadrilateral |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.
Solve for y:
-y - 9 < \( \frac{y}{-2} \)
| y < 2\(\frac{9}{20}\) | |
| y < -18 | |
| y < \(\frac{18}{43}\) | |
| y < \(\frac{8}{13}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-y - 9 < \( \frac{y}{-2} \)
-2 x (-y - 9) < y
(-2 x -y) + (-2 x -9) < y
2y + 18 < y
2y + 18 - y < 0
2y - y < -18
y < -18
y < \( \frac{-18}{1} \)
y < -18
Which of the following is not true about both rectangles and squares?
the area is length x width |
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all interior angles are right angles |
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the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c2 - a2 |
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a2 - c2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)