| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.47 |
| Score | 0% | 49% |
Solve for c:
c2 - 3c + 17 = 5c + 2
| 3 or 5 | |
| 2 or -3 | |
| 2 or -2 | |
| 6 or 2 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 - 3c + 17 = 5c + 2
c2 - 3c + 17 - 2 = 5c
c2 - 3c - 5c + 15 = 0
c2 - 8c + 15 = 0
Next, factor the quadratic equation:
c2 - 8c + 15 = 0
(c - 3)(c - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 3) or (c - 5) must equal zero:
If (c - 3) = 0, c must equal 3
If (c - 5) = 0, c must equal 5
So the solution is that c = 3 or 5
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h2 |
|
4π r2 |
|
π r2h |
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2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
If a = c = 9, b = d = 4, and the blue angle = 52°, what is the area of this parallelogram?
| 30 | |
| 14 | |
| 24 | |
| 36 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 9 x 4
a = 36
Solve b + b = 4b + 5y - 8 for b in terms of y.
| -1\(\frac{3}{5}\)y + 1\(\frac{3}{5}\) | |
| -y - 1 | |
| -1\(\frac{1}{2}\)y + 2\(\frac{1}{2}\) | |
| -1\(\frac{1}{3}\)y + 2\(\frac{2}{3}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
b + y = 4b + 5y - 8
b = 4b + 5y - 8 - y
b - 4b = 5y - 8 - y
-3b = 4y - 8
b = \( \frac{4y - 8}{-3} \)
b = \( \frac{4y}{-3} \) + \( \frac{-8}{-3} \)
b = -1\(\frac{1}{3}\)y + 2\(\frac{2}{3}\)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c2 - a2 |
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c - a |
|
a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)