ASVAB Math Knowledge Practice Test 787757 Results

Your Results Global Average
Questions 5 5
Correct 0 2.47
Score 0% 49%

Review

1

Solve for c:
c2 - 3c + 17 = 5c + 2

48% Answer Correctly
3 or 5
2 or -3
2 or -2
6 or 2

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 3c + 17 = 5c + 2
c2 - 3c + 17 - 2 = 5c
c2 - 3c - 5c + 15 = 0
c2 - 8c + 15 = 0

Next, factor the quadratic equation:

c2 - 8c + 15 = 0
(c - 3)(c - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 3) or (c - 5) must equal zero:

If (c - 3) = 0, c must equal 3
If (c - 5) = 0, c must equal 5

So the solution is that c = 3 or 5


2

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

π r2h2

4π r2

π r2h

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

If a = c = 9, b = d = 4, and the blue angle = 52°, what is the area of this parallelogram?

65% Answer Correctly
30
14
24
36

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 9 x 4
a = 36


4

Solve b + b = 4b + 5y - 8 for b in terms of y.

34% Answer Correctly
-1\(\frac{3}{5}\)y + 1\(\frac{3}{5}\)
-y - 1
-1\(\frac{1}{2}\)y + 2\(\frac{1}{2}\)
-1\(\frac{1}{3}\)y + 2\(\frac{2}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

b + y = 4b + 5y - 8
b = 4b + 5y - 8 - y
b - 4b = 5y - 8 - y
-3b = 4y - 8
b = \( \frac{4y - 8}{-3} \)
b = \( \frac{4y}{-3} \) + \( \frac{-8}{-3} \)
b = -1\(\frac{1}{3}\)y + 2\(\frac{2}{3}\)


5

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 + a2

c2 - a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)