When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + 4c = 6c + 6z + 8 for c in terms of z.
| -\(\frac{2}{15}\)z - \(\frac{8}{15}\) | |
| -17z - 3 | |
| \(\frac{4}{11}\)z + \(\frac{6}{11}\) | |
| z + 1 |