ASVAB Math Knowledge Practice Test 788360 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

If BD = 16 and AD = 20, AB = ?

76% Answer Correctly
1
8
2
4

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 20 - 16
AB = 4


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

diameter

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

A right angle measures:

90% Answer Correctly

360°

45°

180°

90°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


4

Simplify (3a)(6ab) - (3a2)(7b).

62% Answer Correctly
-3a2b
90ab2
3ab2
90a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(6ab) - (3a2)(7b)
(3 x 6)(a x a x b) - (3 x 7)(a2 x b)
(18)(a1+1 x b) - (21)(a2b)
18a2b - 21a2b
-3a2b


5

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
3\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)