When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b + 5b = -8b + 4z - 1 for b in terms of z.
| -\(\frac{1}{11}\)z - \(\frac{1}{11}\) | |
| -\(\frac{3}{10}\)z - \(\frac{3}{5}\) | |
| -1\(\frac{2}{5}\)z - \(\frac{3}{5}\) | |
| 1\(\frac{6}{11}\)z + \(\frac{5}{11}\) |