When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c + 4c = 6c + 9z + 4 for c in terms of z.
| \(\frac{9}{13}\)z - \(\frac{5}{13}\) | |
| -1\(\frac{2}{3}\)z - \(\frac{2}{3}\) | |
| 15z - 7 | |
| -\(\frac{5}{9}\)z - \(\frac{4}{9}\) |