ASVAB Math Knowledge Practice Test 790090

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b - 3b = 6b + 2z - 8 for b in terms of z.

2\(\frac{4}{5}\)z + 1\(\frac{1}{5}\)
-\(\frac{2}{5}\)z - \(\frac{3}{10}\)
-\(\frac{5}{7}\)z + 1\(\frac{1}{7}\)
-1\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)