| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.54 |
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If side a = 8, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{82} \) | |
| \( \sqrt{41} \) | |
| \( \sqrt{65} \) | |
| \( \sqrt{74} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 12
c2 = 64 + 1
c2 = 65
c = \( \sqrt{65} \)
Find the value of c:
-8c + y = -2
-9c + 5y = -6
| \(\frac{37}{57}\) | |
| \(\frac{4}{31}\) | |
| 6 | |
| -\(\frac{39}{47}\) |
You need to find the value of c so solve the first equation in terms of y:
-8c + y = -2
y = -2 + 8c
then substitute the result (-2 - -8c) into the second equation:
-9c + 5(-2 + 8c) = -6
-9c + (5 x -2) + (5 x 8c) = -6
-9c - 10 + 40c = -6
-9c + 40c = -6 + 10
31c = 4
c = \( \frac{4}{31} \)
c = \(\frac{4}{31}\)
Factor y2 - 5y - 24
| (y + 8)(y + 3) | |
| (y - 8)(y - 3) | |
| (y - 8)(y + 3) | |
| (y + 8)(y - 3) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -24 as well and sum (Inside, Outside) to equal -5. For this problem, those two numbers are -8 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 5y - 24
y2 + (-8 + 3)y + (-8 x 3)
(y - 8)(y + 3)
On this circle, line segment CD is the:
chord |
|
radius |
|
circumference |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for c:
c2 + 2c - 1 = -2c + 4
| 4 or -6 | |
| 1 or -5 | |
| -2 or -9 | |
| -6 or -7 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 + 2c - 1 = -2c + 4
c2 + 2c - 1 - 4 = -2c
c2 + 2c + 2c - 5 = 0
c2 + 4c - 5 = 0
Next, factor the quadratic equation:
c2 + 4c - 5 = 0
(c - 1)(c + 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 1) or (c + 5) must equal zero:
If (c - 1) = 0, c must equal 1
If (c + 5) = 0, c must equal -5
So the solution is that c = 1 or -5