ASVAB Math Knowledge Practice Test 790332

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c - 2c = -8c - 5y + 2 for c in terms of y.

y + \(\frac{1}{8}\)
-4\(\frac{1}{3}\)y - 1\(\frac{1}{3}\)
-1\(\frac{1}{3}\)y - \(\frac{5}{6}\)
-1\(\frac{1}{2}\)y + 1