ASVAB Math Knowledge Practice Test 790524

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c - 9c = -c + 7z + 3 for c in terms of z.

\(\frac{1}{2}\)z - 4
-\(\frac{4}{7}\)z - \(\frac{5}{14}\)
1\(\frac{1}{4}\)z - 1
2\(\frac{2}{7}\)z + \(\frac{3}{7}\)